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Let f(x) =1-x and g (x) = x^3+4, find (f°g)(0)

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(f ○ g)(0) = - 3

evaluate g(0) and substitute the value into f(x)

g(0) = 0 + 4 = 4

f(4) = 1 - 4 = - 3

thus (f ○ g)(0) = - 3


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