The square root of 88 is
![2√(22)](https://img.qammunity.org/2019/formulas/mathematics/college/gmynuyzzydw4jol31hfv54oo04iil1catd.png)
Working:
As prime factorization of 88 is = 2³*11
here, 88 divides by 2, it becomes= 2*44
44 divides by 2 = 2*22, so 88 becomes 2*2*22
22 divides by 2 = 2*11, so 88 becomes 2*2*2*11
This gives us 2³*11
now, square root of this is:
![√(2*2*2*11)](https://img.qammunity.org/2019/formulas/mathematics/college/2dey0w6jept0xz6yn77ree7icb9lkxaj4z.png)
=
![\sqrt{2^(2)} *√(2*11)](https://img.qammunity.org/2019/formulas/mathematics/college/md6ugq30hq3zqqyhq3f1qmizyn87w6phy5.png)
As,
=2
Final solution becomes:
![2√(2*11)](https://img.qammunity.org/2019/formulas/mathematics/college/tqj0astolme4bjfuanytl047oe1y72t7w0.png)
=
![2√(22)](https://img.qammunity.org/2019/formulas/mathematics/college/gmynuyzzydw4jol31hfv54oo04iil1catd.png)