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You want to calculate the displacement of an object thrown over a bridge. Using -10 m/s^2 for acceleration due to gravity, what would be the total displacement of the object if it took 8 seconds before hitting the water? SHOW YOUR WORK!

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Answer

The total displacement of the object is 320 m

Solution-

From the formulas of mechanics,


s=ut+(1)/(2)at^(2)

Where,

s = displacement

u = initial velocity = 0 ( ∵ As the body was in rest in the beginning )

t = time taken = 8 s

a = acceleration = -10 m/s² ( ∵ -ve is because of the downward motion)

Putting all the values,


s= 0 * 8 + (1)/(2)(-10)8^(2) = -320 \ m ( ∵ -ve displacement means it is in downwards)

User Eugene Brusov
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