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Write the series 2+4+6+8+...+100 in sigma notation

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We need to write the sum in this form:


\displaystyle \sum_(i=1)^N a_i

So, we need to find an appropriate sequence, such that
a_i is the i-th even number.

You can easily check that this series is
a_i=2i. In fact, you have


\begin{array}ca_1&2\cdot 1&2\\a_2&2\cdot 2&4\\a_3&2\cdot 3&6\\a_4&2\cdot4&8\end{array}

and so on. Finally, we have to observe that we want the first 50 elements of this sequence, since
a_(50) = 2\cdot 50 = 100.

So, the sum can be written as


\displaystyle \sum_(i=1)^(50) 2i

User Prabhu
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