Question

There are two cables coming off the top of a building from the same point. Each cable is secured to the ground. The longest cable is 200 ft. It is attached at point M and creates a 32° angle of elevation with the ground. The other cable is attached at point N. If the angle formed between the two cables at the top of the building is 25°, what is the distance between points M and N?

Measure of Ð N =
°

Answer 1

N= 123

x= 100.8

Explanation:

I just did it

Answer 2

Call the point of attachment at the top of the building point T. (Angle T = 25°) The angle N = 180° -32° -25° = 123°. The Law of Sines tells you the relationship ...

... TM/sin(N) = MN/sin(T)

... MN = TM·sin(T)/sin(N) = (200 ft)·sin(25°)/sin(123°)

... MN ≈ 100.8 ft