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The graph of y=tan{1/4(x-pi/2)}+1 is shown what is the period of the function

2 Answers

2 votes

Answer:

4pi

5pi/2+4npi

7pi/2+4npi

Explanation:

2023 edge

User Fiter
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2 votes

Answer:

The period is : 4pi

The asymptotes are: 5pi/2 + 4npi

The x-intercepts are: 7pi/2 + 4npi

I had a hard with this assignment, so here are the answers for the whole thing:

1.) [A] vertical shift

2.) [D] horizontal stretch

3.) given in the original answer

4.) [C] y = 3tan(x) + 2

5.) reflected across the x-axis

shifted 3 units down

stretched vertically

shifted 4 units left

6.) [D] y = -tan(x - pi/2)

7.)Start by graphing the tangent function.Compress the graph horizontally by making the period one-half pi.Reflect the graph over the x-axis.Shift the graph up 3 units

User Lpfavreau
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7.8k points