Question

What are the excluded values? -7/k^2-2x-15

Answer 1

Answer : the excluded value is 5 and -3

Explanation:

Since we have
`(-7)/(k^2-2k-15)`

So, the denominator is
`k^2-2k-15`

By splitting the middle term we get,

`k^2-2k-15=0\\k^2-5k+3k-15=0\\k(k-5)+3(k-5)=0\\(k-5)(k+3)=0\\k-5=0;k+3=0\\k=5 \text{and } k=-3`

So, the excluded value will be 5 and -3

i.e K can't take the value as 5 and -3 otherwise it becomes not defined .