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A small airplane loses a bolt while traveling at a speed of 150.0 meter/second in the horizontal direction. The bolt follows a parabolic patch and lands on the ground after 25 seconds. How far will the bolt have traveled horizontally from the point where it left the plane until it lands on the ground?

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Answer:

Bolt will travel a distance of 3750 meter horizontally from the point where it left the plane until it lands on the ground.

Step-by-step explanation:

We have equation of motion ,
s= ut+(1)/(2) at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Here bolt has horizontal and vertical motion, but the horizontal velocity remains same because there is no acceleration acting in the horizontal direction.

In this case initial velocity = 150 m/s, time taken to reach ground = 25 seconds and acceleration is zero.

Substituting


s= 150*25+(1)/(2)*0*25^2\\ \\ s=3750 meter

So bolt will travel a distance of 3750 meter horizontally from the point where it left the plane until it lands on the ground.

User Brad Budlong
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