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Mid point of countinious AB if A=(-2,2) and B = (3,-1)

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-2+3= -1/2

2+(-1)= 2-1= 1

Midpoint= (-1/2, 1)

The formula is (x1+x2)/2, (y1+y2)/2

User Circy
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Remark

The midpoint of any line has a definite formula. All you need do is define the formula parts in terms of the points.

Formula

x = (x1 + x2)/2

y = (y1 + y2)/2

Givens

x1 = -2

x2 = 3

y1 = 2

y2 = -1

Solution

x = (-2+3)/2 = 1/2

y = (2 + -1)/2 = 1/2

Answer

The midpoint is (1/2,1/2)

User Fresidue
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