Question

Calculate the acceleration of the object during the first two seconds

Answer 1

The acceleration of the object during the first two seconds is 1.5
`(m)/(s^(2) )`.

Step-by-step explanation:

At t = 2 s, velocity of the object is 3 m/s

At t = 0 s, velocity of the object is 0 m/s

Acceleration is define as rate of change of velocity with time.

∴Acceleration =
`(v_(f) -v_(i) )/(t_(f) - t_(i)  )`

Acceleration =
`(v_(2) -v_(0) )/(t_(2) - t_(0)  )`

Acceleration =
`(3-0 )/(2-0  )`

Acceleration = 1.5
`(m)/(s^(2) )`

The acceleration of the object during the first two seconds is 1.5
`(m)/(s^(2) )`.