Question

Write the equation of the line that passes through -5,1 and 2,1 in the form y=mx+b

Answer 1

First, let's find the slope of the line segment that passes through the given poins (-5,1) and (2,1). (Note: Please use parentheses here.

1-1

m = -------------- = 0. The slope of this segment is zero; the segment is horiz.

2-(-5)

The desired line is therefore horiz. It passes thru (-5,1) and (2,1). Note that the y-coordinates are both 1. Thus, the equation of this horiz. line is y = 1.

Answer 2

-5,1 and 2,1

M= y2-y1/x2-x1

M=1-1/2-(-5)

M=0/7

M=0

Y=mx+b

(2,1)

1=0(2)+b

1=b

Y=1