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Find angle sin (A) of the right triangle if side a = 6 and side b = 15

sin (A) =
The way I did it I got 15/17 but that was wrong.

Find angle sin (A) of the right triangle if side a = 6 and side b = 15 sin (A) = The-example-1

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Given that side a = 6
side b = 15

Use Pythagoras theorem to find out hypotenuse, h.


{h}^(2) = {a}^(2) + {b}^(2) \\ \\ {h}^(2) = {6}^(2) + {15}^(2) \\ \\ {h}^(2) = 36 + 225 = 261 \\ \\ h = √(261)


\text{We know that } \sin(A) = (b)/(h) \\ \\thus \: \boxed{ \red{ \sin(A) = (15)/( √(261) ) }}
User Meetu Choudhary
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