Question

Find the equation perpendicular to the line y=−3x+5 that passes through point (2, 6).

Please answer quickly. Will give 70 points

Answer 1

Perpendicular lines have slopes whose product is -1.

If the original line has slope 3, the line that is perpendicular has slope -(1/3) Now use the point slope form of the line.

y - y1 = m(x - x1)

If (x1,y1) = (2,2) - your point, then:

y - 2 = (-1/3)(x - 2)

you can convert this into slope-intercept form.

y - 2 = (-1/3)x + (2/3)

y = (-1/3)x +(8/3)

Both equations represent the same line.

Answer 2

for a line to be perpendicular, the product of its slope and the given slope must be equal to -1
so..

`( - 1)/( - 3) = (1)/(3)`

now we need to find our y-intercept
we use the given coordinate and our new slope find this

`y - intercept = 5 (1)/(3) = (16)/(3)`

now to put these together into our final equation

`y = (1)/(3) x + (16)/(3)`