2 Answers

Daniel Gray · Answer 1 · 2019-08-25T07:52:12+0000

Number of small boxes = x

Number of large boxes = y

she has at least 4 small boxes.

$x \geqslant 4$

Number of large boxes can be 0 or more.

$y \geqslant 0$

Maximum weight = 80lb

$5x + 12y \leqslant 80$

These are the required equations.

Martin Dzhonov · Answer 2 · 2019-08-29T16:42:19+0000

Your job looks correct. The number of small boxes is x, and we know that she has at least 4 of them so we have
$x \geq 4$ .

We have no information about the number of large boxes, so the first two options make no sense.

Also, x boxes weighing 5lb and y boxes weighing 12lb sum up to
5x+12y , and this weight can be at most 80, so we have

$5x+12y \leq 80$

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