Question

Write the equation of a line that is perpendicular to y=0.3x+6 and that passes through the point (3,-8)

Answer 1

First, find the perpendicular slope

y = 0.3x + 6 ⇒ m = 0.3 =
`(3)/(10)`

perpendicular slope =
`-(10)/(3)`

Next, input the point (x₁, y₁) and slope (m) into the Point-Slope formula

y - y₁ = m(x - x₁)

y - (-8) =
`-(10)/(3)`(x - 3)

y + 8 =
`-(10)/(3)x` + 10

y =
`-(10)/(3)` + 2