Question

Write the equation of a line that is parallel to y=0.6x+3 and that passes through the point

(-3,-5)

Answer 1

A line parallel to y = 0.6x + 3 will be of the form:


`y = 0.6x + k`

where k is a constant.

It passes through (-3,-5)

Thus,


`y = 0.6x + k \\ \\ -5 = 0.6 * (-3) + k \\ \\ -5 = -1.8 + k \\ \\k = -5 + 1.8 \\ \\ k = -3.2`


`\textbf{The equation is \: \: y = 0.6x - 3.2}`