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How many solutions does the following equation have? 12z- 6 + 15z = 27z- 5
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How many solutions does the following equation have? 12z- 6 + 15z = 27z- 5

User Paul Serre
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WHO CARE Explanation:

i do XD

User Coccoinomane
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Zero because you combine 12z and 15z because they are like terms giving you 27z. The equation now looks like 27z-6=27z-5. Subtract 27z on both sides leaving you -6=-5 which is false. So the equation has 0 solutions.
User GRardB
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