Question

Marty is three years younger than six times his friend wants age. The sum of their ages is greater than 11. What is the youngest age warren

can be

Answer 1

Let M = Marty's age, and W = Warren's age

M+3 = 6W

Solve for M: M = 6W - 3 {Eqn 1}

M + W > 11 {Eqn 2}

Now you have two equations (Eqn 1 & 2}, and two unknowns (M, W)

There are a couple of ways to proceed. I recommend rewriting Eqn 2 as M + W = 11. Now you can easily use substitution. Solving for M yields M = 11-W. Now plug this back into Eqn 1:

11-W + 3 = 6W

14 = 7W

W =2