Question

A bullet leaves a gun with a horizontal velocity of 100 m/s. Calculate the distance it would travel in 1.3 seconds.

a 1247 m
b 0.013 m
c 130 m
d 76.92 m

Answer 1

Option C is the correct answer

Step-by-step explanation:

We have equation of motion ,
`s= ut+(1)/(2) at^2`, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case initial velocity = horizontal velocity = 100 m/s, acceleration = 0
`m/s^2`, we need to calculate displacement when time = 1.3 seconds.

Substituting

`s= 100*1.3+(1)/(2) *0*1.3^2 = 130 meter`

So, bullet will travel a distance of 130 meter in 1.3 seconds.

Option C is the correct answer