Question

Find three consecutive even integers. Such that 4 times of first integer is 18 more than the sum of second and third integers

Answer 1

integers:

x

x + 2

x + 4

4x - (x + 4) = 2 (x + 2) + 6

3x - 4 = 2x + 4 + 6

3x - 4 = 2x + 10

x = 14

integers: 14, 16, 18

check answer: 4 (14) - 18 = 2 (16) + 6

38 = 38