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Find the domain of f(x)= sqrt2-9x
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Find the domain of f(x)= sqrt2-9x

User Hradecek
by
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1 Answer

4 votes

f(x) =
√(2 - 9x)

2 - 9x ≥ 0

- 9x ≥ - 2


(-9x)/(-9) \geq (-2)/(-9)

x ≤
(2)/(9)

Interval Notation: (-∞,
(2)/(9)]

User Waltzy
by
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