Question

if an object is projected upward with an initial velocity of 127 ft per sec, its height h after t seconds is h=−16t2+127t. Find the height of the object after 4 seconds.

Answer 1

You are given a function
`h(t)=-16t^2+127t.` This function shows you the dependence of height from time.

To find the height of the object after 4 seconds, you should substitute t=4 into the function expression:

`h(4)=-16\cdot 4^2+127\cdot 4=-16\cdot 16+508=-256+508=252\ ft.`

Answer: the height of the object after 4 seconds will be 252 ft.