(- ∞, -) ∪ (- , ∞ )
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.
solve : 8x + 3 = 0 ⇒ x = -
8x + 3 ≠ 0
8x ≠ -3
x ≠
Interval Notation: (∞, ) U ( , ∞)
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