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Given cscx/cotx=sqrt2, find a numerical value of one trigonometric function of x.

User Laizer
by
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2 Answers

3 votes

Answer: secx=
√(2)

Explanation:

A on edge

User Lendmann
by
7.7k points
2 votes


(csc (x))/(cot (x)) = √(2)


(csc (x))/(1) * (1)/(cot (x)) = √(2)


(1)/(sin (x)) * (sin(x))/(cos (x)) = √(2)


(1)/(cos (x)) = √(2) ; sin(x) ≠ 0, cos(x) ≠ 0


(cos (x))/(1) = (1)/(√(2)); sin(x) ≠ 0, cos(x) ≠ 0


cos (x) = (√(2))/(2)

Use the Unit Circle to determine when
cos (x) = (√(2))/(2)

Answer: 45° and 315°
((\pi)/(4) and (7\pi )/(4) )


User Sofi
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6.6k points