Question

A gas at 76 K is under a pressure of 78.4 kPa. If the temperature changes to 105 what will be the new

pressure?

Answer 1

108.3kPa

Step-by-step explanation:

Given parameters:

Initial temperature = 76k

Initial pressure = 78.4kPa

Final temperature = 105k

Unknown:

Final or new pressure = ?

Solution:

To solve this problem, we apply the combined gas law:

`(P_(1) )/(T_(1) )` =
`(P_(2) )/(T_(2) )`

T1 = 76k

P1 = 78.4kPa

T2 = 105k

`(78.4)/(76)` =
`(P_(2) )/(105)`

P2 = 108.3atm