Question

if an object is projected upwards with an angle 30 to the horizontal and its initial velocity is 20 m/s, its maximum height= ? ( consider g= 10m/s^2 )

Answer 1

`h_m=5 \ m`

Step-by-step explanation:

Projectile Motion

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path under the action of gravity.

The maximum height hm is reached when the vertical component of the velocity is 0. It can be calculated as follows:

`\displaystyle h_m=(v_o^2\cdot \sin^2\theta)/(2g)`

Where:

vo = initial speed of the object

θ = initial launch angle

g = acceleration of gravity (
`10\ m/s^2`)

The object is projected with an angle of θ=30° and an initial speed of vo=20 m/s. The maximum height is:

`\displaystyle h_m=(20^2\cdot \sin^2 30^\circ)/(2*10)`

`\displaystyle h_m=(400\cdot 0.5^2)/(20)`

`\boxed{h_m=5 \ m}`