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How do I find the value of each variable??

How do I find the value of each variable??-example-1

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What we should know is x= 6y-2. y=4x+20

Plug them in, and you get:

y= 4 (6y-2) + 20 , x= 6 (4x+20)-2.

y= 24y-8+20, x=24x+120-2

y=24y+12, x=24x+118

y-24y=24y+12-24y (subtract 24y both sides) to cancell out the coefficient 24y and you should be left with -23y=12, having 24 y cancelled and y-24y=-23y.

Then, divide both sides by -23 to isolate the variable, y. You should get -12/23 as the vertice, y.

For x, where we left off with x=24x+118, flip the equation. 24x+118=x Then add -118 on both sides to balance the equation out. Then, after resulting in 24x=y-118 (because adding negative 118 cancells out its positive, and y+-118 is y-118) isolate the variable by dividing the coefficient 24x by its constant-part, 24, on both sides to satisy the equation. The answer is or should be x=1/24y+ -59/12 . I hope this really helps. If you need any other algebra help, I recommend mathpapa.com or symbolab to help you simplify equations with just a series of steps to take. Again, I hope for the best! :)

User Nick Coad
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Isosceles, so

6y - 2 = 4x + 20

4x - 6y = -22

Also, the angles add to 180 degrees,

52 + (6y - 2) + (4x + 20) = 180

4x + 6y = 180 - 52 + 2 - 20 = 110

Adding

8x = 88

x = 11

6y = 110 - 4 x = 110 - 44 = 66

y = 11

Answer: x=11, y=11


User Alex Bush
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8.1k points

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