Question

What are the components of vector B if it’s magnitude is 18 m and makes an angle of 112 degrees with the +x- axis?

Answer 1

Any vector can be written as components along positive X and positive Y axes.

So vector B can be written as
`Bcos(\theta)i+Bsin(\theta)j`, where
`\theta` is the angle between vector and positive X axis

So vector B =
`18*cos(112)i+18*sin(112)j=-6.74i+16.69j`

So components of vector B along X -axis =-6.74 m

along Y-axis = 16.69 m