a. At the end of 6 yards, the temperature drops to 70 - 5(2) = 70 - 10
= 60 F
Since from 6 yards to 15 yards, the temperature is constant, the temperature at 10 yards below the surface is 60F.
b. 50 feet is approximately 17 yards.
Since the temperature increases 3F per foot after 15 yards,
Increase in temperature after 15 yards = 17 - 14 = 3 yards
= 3(3) = 9 feet
The temperature at 50 feet below the surface = 60 + 3(9)
= 87 F
c. Please check the expression in the image attached.
Since 1 yard = 3 feet, and the temperature increases 3F per foot, from 15 yards,
the temperature = 60 + (t - 14)(3)(3)
= 60 + 9(t - 14)
= 60 + 9t - 126
= 9t - 66