Question

an object at rest starts accelerating if it travels 30 meters to end up going 10 m/s what was it’s acceleration

Answer 1

First we have to calculate the time taken to travel the distance 30 m, is

`t = (distance)/(velocity) = (30 \ m)/(10 \ m/s ) =  3 \ s`.

Now from equation of motion,

`v = u + at`

Given,
`v = 10 \ m/s` .

As object starts from rest, so u = 0.

Substituting these values in above equation, we get

`10 \ m/s = 0 + a * 3 \ s \\\\ a = (10)/(3)  = 3.33 \ m/s^2`.

Thus, the acceleration is
`3.33 \ m/s^2`