Question

The perimeter of a square is 56cm. What is the approximate length of its diagonal?

Answer 1

To find the answer, we can use the Pythagoras theorem, where:

`\sqrt{a^(2)+ b^(2) } =c^(2)`

Where a and b is the side length and c is the diagonal.

In this case:

`\sqrt{56^(2) +56^(2) } </p><p>\\ =√(6272) \\ =79.19596... \\ =79.2(correct to 3 sig. fig.)`

Therefore, the answer is 79.2cm

Hope it helps!