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The sum of two integers is 74. The larger is 26 more than twice the smaller. Find the two integers.

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n - the larger of two i ntegers

m - the smaller of two integers

n + m = 74 → n = 74 - m

n = 2m + 26

Therefore we have:

2m + 26 = 74 - m |subtract 26 from both sides

2m = 48 - m |add m to both sides

3m = 48 |divide both sides by 3

m = 16

n = 74 - 16 = 58

Answer: 16 and 58.

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