2 Answers

Azhidkov · Answer 1 · 2019-10-23T03:37:50+0000

Answer:

(11)/(20)

Explanation:

Total male students = 200

Students who play football (F)= 58

Students who play basketball (B)= 40

Students who play both (F∩B)= 8

The number of students who play either sport is

$(F\cup B)=F+B-(F\cap B)$

$(F\cup B)=58+40-8=90$

The number of students who play neither sport is

$200-(F\cup B)=200-90=110$

The probability that a randomly selected male student plays neither sport is

$Probability=\frac{\text{Number of students who play neither sport}}{\text{Total male students}}$

Probability=(110)/(200)

Probability=(11)/(20)

Hence, the required probability is
(11)/(20) .

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