Question

Three consecutive odd integers whose sum is 366

Answer 1

n, n + 2, n + 4 - three consecutive odd integers

366 - the sum

Equation:

n + (n + 2) + (n + 4) = 366

n + n + 2 + n + 4 = 366

3n + 6 = 366 |subtract 6 from both sides

3n = 360 |divide both sides by 3

n = 120

n + 2 = 120 + 2 = 122

n + 4 = 120 + 4 = 124

Answer: 120, 122, 124.