The remaining balances in the first and second account are $5805 and $1020 respectively.
Step-by-step explanation
Suppose, the initial balance in the first account was
dollar.
As the total amount in two accounts was $9000, so the initial balance in the second account was
![(9000-x) dollar](https://img.qammunity.org/2019/formulas/mathematics/high-school/m1zb0x7gc1l6ldns9aklhd2eszzfezhrfe.png)
He withdrew 10% from the first and 60% from the second account to buy the ring which cost $2175. So, the equation will be......
![0.10x+0.60(9000-x)=2175\\ \\ 0.10x+5400-0.60x=2175\\ \\ -0.50x= 2175-5400= -3225\\ \\ x=(-3225)/(-0.50)= 6450](https://img.qammunity.org/2019/formulas/mathematics/high-school/gevd53q4ii037belqpohkfhadtyoz5onlo.png)
So, the initial balance in the first account was $6450 and in the second account was ($9000 - $6450)= $2550
Thus, the remaining balance in the first account = 90% of $6450 =
and the remaining balance in the second account = 40% of $2550 =
![(0.40*2550)=\$1020](https://img.qammunity.org/2019/formulas/mathematics/high-school/kzuoemb5qw1c3osnyg4089sf0i11srmzgx.png)