Question

If you burn 33.1 g of hydrogen and produce 295 g of water, how much oxygen reacted?

Answer 1

262 g of O₂

Step-by-step explanation:

First we will find out that either the given amount of Hydrogen gas can produce 295 g of H₂O or not. Therefore, the Balanced Chemical Equation is as,

2 H₂ + O₂ → 2 H₂O

According to equation,

4.04 g (2 mol) H₂ forms = 36.04 g (2 mol) H₂O

So,

33.1 g H₂ will produce = X g of H₂O

Solving for X,

X = (33.1 g × 36.04 g) ÷ 4.04 g

X = 295 g of H₂O

Hence it is proved that given mass of H₂ can produce 295 g of H₂O.

The amount of oxygen reacted is calculated as,

According to equation,

4.04 g (2 mol) H₂ reacts with = 32 g (1 mol) O₂

So,

33.1 g H₂ will react with = X g of O₂

Solving for X,

X = (33.1 g × 32 g) ÷ 4.04 g

X = 262 g of O₂