Question

When the [h+] in a solution is 1.7 × 10−9 m, what is the poh ? A. 8.80 b. 5.23 c. 14 d. 8.60

Answer 1

pH=-log[H+]
PH=-log 1.7x10E-9
pH=8.77

SINCE THEY ASK YOU FOR pOH just use the formula.

pH+pOH=14
pOH=14-pH
pOH=14-8.77
pOh=5.23

Answer 2

Answer : The correct option is, (B) 5.23

Explanation :

pH : It is defined as the negative logarithm of hydrogen ion concentration.

Mathematically, it is represented as :

`pH=-\log [H^+]`

First we have to calculate the pH.

`pH=-\log [H^+]`

`pH=-\log (1.7* 10^(-9))`

`pH=8.77`

Now we have to calculate the pOH.

`pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-8.77=5.23`

Therefore, the pOH of the solution is, 5.23