Question

Find a Cubic function with zeros 3, -4, and 6

Answer 1

x = 3 x = -4 x = 6

x - 3 = 0 x + 4 = 0 x - 6 = 0

(x - 3)(x + 4)(x - 6) = 0

(x² + x - 12)(x - 6) = 0 (x - 3)(x + 4) = x² + 4x - 3x - 12 = x² + x - 12

x³ - 6x² + x² - 6x - 12x + 72 = 0

x³ - 5x² -18x + 72 = 0

Answer: x³ - 5x² - 18x + 72 = 0