Let us consider two bodies having masses m and m' respectively.
Let they are separated by a distance of r from each other.
As per the Newtons law of gravitation ,the gravitational force between two bodies is given as -
where G is the gravitational force constant.
From the above we see that F ∝ mm' and
![F\alpha (1)/(r^(2) )](https://img.qammunity.org/2019/formulas/physics/college/um23r3o39zrh2ballpbi5210gbgrgut5su.png)
Let the orbital radius of planet A is
= r and mass of planet is
.
Let the mass of central star is m .
Hence the gravitational force for planet A is
![f_(1) =G (m_(1)*m )/(r^(2) )](https://img.qammunity.org/2019/formulas/physics/college/fsqwdgb452vkovxkwvarj1q1r19tc83jy7.png)
For planet B the orbital radius
and mass
Hence the gravitational force
![f_(2) =G(m m_(2) )/(r^(2) )](https://img.qammunity.org/2019/formulas/physics/college/5jz7tddhje7o3f8zclbstvlz0sobo12ksn.png)
![f_(2) =G(m*3m_(1) )/([2r_(1)] ^(2) )](https://img.qammunity.org/2019/formulas/physics/college/p0ciyz4dwhfx4e3nhwo37w9ucos4jm5kxz.png)
![= (3)/(4) G(mm_(1) )/(r_(1) ^(2) )](https://img.qammunity.org/2019/formulas/physics/college/rgtg2gc2zqrvri0dl269da8bmki53zl8mn.png)
Hence the ratio is
![(f_(2) )/(f_(1) ) = \frac{(3)/(4)G mm_{1/r_(1) ^2} }{Gmm_(1)/r_(1) ^2 }](https://img.qammunity.org/2019/formulas/physics/college/8e5b3byvl8u4snctsgmqsogs4m1mgjk54u.png)
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