Question

Please help and show work if you can​

Answer 1

38. <1 =
`38^(o)`, <2 =
`32^(o)`, <3 =
`110^(o)`

39. <1 =
`71^(o)`, <2 =
`28^(o)`, and <3 =
`81^(o)`

Explanation:

38. Sum of angles in a triangle =
`180^(o)`

So that;

38 + 110 + <2 =
`180^(o)`

148 + <2 =
`180^(o)`

<2 =
`180^(o)` - 148

<2 =
`32^(o)`

Thus,

<1 =
`38^(o)` (alternate angle principle)

<3 =
`110^(o)`

Therefore;

<1 =
`38^(o)`, <2 =
`32^(o)`, <3 =
`110^(o)`

39. <2 =
`28^(o)` (alternate angle principle)

So that;

sum of angles in a triangle =
`180^(o)`

<1 + <2 + 81 =
`180^(o)`

<1 +
`28^(o)` + 81 =
`180^(o)`

<1 + 109 =
`180^(o)`

<1 =
`180^(o)` - 109

=
`71^(o)`

<1 =
`71^(o)`

<3 =
`81^(o)`

<1 =
`71^(o)`, <2 =
`28^(o)`, and <3 =
`81^(o)`