Answer:
The difference of
is
![\mathbf{(x-17)/(3x)}](https://img.qammunity.org/2022/formulas/mathematics/high-school/wix0k3ki7aik67y52lzzfxqstx5h1gu7dj.png)
Explanation:
We need to find the difference:
![(x-8)/(3x)-(3x)/(x^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/lhl7x7zre5ozwlyw0muor06t5rjgl64p5o.png)
Simplifying to find the difference:
![(x-8)/(3x)-(3x)/(x^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/lhl7x7zre5ozwlyw0muor06t5rjgl64p5o.png)
x is common in both 3x and x^2 so, we can cancel it out and we get:
![=(x-8)/(3x)-(3x)/(x(x))\\=(x-8)/(3x)-(3)/(x)](https://img.qammunity.org/2022/formulas/mathematics/high-school/une74ff3jebwe6pexsqdcfyb4tyj4ix1wd.png)
Now, taking LCM of 3x and x we get 3x, We will multiply 3x with both terms and then solve we get:
![=(x-8-3(3))/(3x)\\=(x-8-9)/(3x)\\=(x-17)/(3x)](https://img.qammunity.org/2022/formulas/mathematics/high-school/5s5yi613w5uvvtmz5d1rn11fbeytnoxzyq.png)
It cannot be further simplified, so we get
as answer.
So, The difference of
is
![\mathbf{(x-17)/(3x)}](https://img.qammunity.org/2022/formulas/mathematics/high-school/wix0k3ki7aik67y52lzzfxqstx5h1gu7dj.png)