Question

You work as a cashier for a bookstore and earn $6 per hour. You also baby sit and earn $6 per hour. You want to earn at least $60 per week, but would like to work no more than 12 hours per week.

Which system of inequalities, along with y ≥ 0 and x ≥ 0, would you use to solve the real-world problem?

Answer 1

y<-x+12,

y>-x+10.

That is the most logical answer hope it helps

(even though its late D; sorry)

Answer 2

y ≤ -x + 12

y ≥ - x + 10

Option 1 is correct

Explanation:

A cashier for a bookstore and earn $6 per hour.

A cashier baby sit and earn $6 per hour.

Let a cashier sit at bookstore for "x" hours and his baby sit for "y" hours

To earn at least $60 per week,

Therefore, 6x + 6y ≥ 60

or x + y ≥ 10 or y ≥ - x + 10

They would like to work no more than 12 hours per week.

Therefore, x + y ≤ 12

or y ≤ -x + 12

Along with y ≥ 0 and x ≥ 0

System of inequalities:

y ≤ -x + 12

y ≥ - x + 10