Question

Calculate the extension of a 20cm spring that has a spring contrast of 45000N/m and 1500N of elastic potential energy.

Answer 1

See the answer below

Step-by-step explanation:

The elastic potential energy can be calculated by means of the following equation:

`E_(el)=(1)/(2) *k*x^(2)`

where:

Eel = elastic energy = 1500 [J]

k = spring constant = 45000 [N/m]

x = extension [m]

`1500=(1)/(2) *45000*x^(2) \\3000=45000*x^(2) \\x=√(0.06666)\\x=0.258[m] = 25.8 [cm]`