Question

Please help and show work if you can ​

Answer 1

14. x = 6, y = 8

15. x = 5, y = 7

16. x = 7, y = 10

Explanation:

For a parallelogram, the length across the point of intersection of its diagonals are equal.

So that;

14. PT = TR

QT = TS

So that,

2x = y + 4

2x - y = 4 ...........1

x + 2 = y

x - y = -2 ............. 2

subtract equation 2 from 1,

x = 6

substitute the value of x in equation 1,

2 x 6 - y = 4

y = 12 - 4

= 8

x = 6, y = 8

15. PT = TR

QT = TS

x + 2 = y

x - y = -2 .......... 1

2x = y + 3

2x - y = 3 ......... 2

Subtract equation 1 from 2

x = 5

substitute the value of x in equation 1

5 - y = -2

5 + 2 = y

y = 7

x = 5, y = 7

16. PT = TR

QT = TS

y = x + 3

x - y = -3 ......... 1

2y = 3x -1

3x - 2y = 1 ......... 2

Multiply equation 1 by 2 to have;

2x - 2y = -6 ....... 3

subtract equation 3 from 2

x = 7

substitute the value of x in equation 1

7 - y = -3

-y = -7 -3

-y = -10

multiply through by minus

y = 10

x = 7, y = 10