Question

Need help with this math

Answer 1

a)

`(\$0.10)/(1000\,Wh)* 50\,W* 9\,h=(\$0.10\cdot 50\cdot 9)/(1000)=\bf{\$0.045}`

b) The cost per year is 365 times this amount. You save 35/50 times that, so you save ...

... $0.045×365×35/50 = $11.4975 ≈ $11.50 . . . annual savings

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If the bulb is using 15 W instead of 50 W, you are saving the cost of 50-15=35 W, so 35/50 of the cost of running the higher-power bulb.