we are given
• 6 science-fiction stories
• 4 adventure stories
• 3 historical stories
• 2 sports stories
so,
total number of stories =6+4+3+2
total number of stories =15
Probability of selecting science stories:
number of science stories =6
total number of stories =15
P(S)=(number of science stories)/(total number of stories)
![p(S)=(6)/(15)](https://img.qammunity.org/2019/formulas/mathematics/high-school/f7k1r594sf84rk2bfqrfc2brt0gt1p3agu.png)
![p(S)=(2)/(5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/yjg2bpcf36ref87116gn3lzufgwdhlgtqm.png)
Probability of selecting adventure stories:
number of adventure stories =4
total number of stories =15
P(A)=(number of adventure stories)/(total number of stories)
![p(A)=(4)/(15)](https://img.qammunity.org/2019/formulas/mathematics/high-school/c8lhld0tfhf3aimyjge12b43afqeqp33zh.png)
![p(A)=(4)/(15)](https://img.qammunity.org/2019/formulas/mathematics/high-school/c8lhld0tfhf3aimyjge12b43afqeqp33zh.png)
now, we can find
the probability that the story Artie selects is either a science-fiction story or an adventure story
that is P(AUS)
p(AUS)=p(A)+p(S)-p(A∩S)
we know that
p(A) and p(S) are independent
so,
p(A∩S)=p(A)*p(S)
we can plug it
p(AUS)=p(A)+p(S)-p(A)*p(S)
we get
p(AUS)=
![(2)/(5)+(4)/(15)- (2)/(5)*(4)/(15)](https://img.qammunity.org/2019/formulas/mathematics/high-school/90z4ifv1naqo3fikhr6jbr4uv1ei4gefov.png)
p(AUS)=
...........Answer