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Given: PQ ⊥ QR , PR=20, SR=11, QS=5 Find: The value of PS.

Given: PQ ⊥ QR , PR=20, SR=11, QS=5 Find: The value of PS.-example-1

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1. PQR and is a right triangle, so you can calculate the measure of PQ by applying the Pythagorean Theorem. PR is the hypotenuse and QR and PQ are the legs:


PR^(2)=PQ^(2)+QR^(2)\\ PQ=\sqrt{PR^(2)-QR^(2)}\\ PQ=\sqrt{20^(2)-16^(2)} \\ PQ=12

2. PQS and is a right triangle too, so you can calculate the measure of PS by applying the Pythagorean Theorem as above. PS is the hypotenuse and PQ and QS are the legs:


PS=\sqrt{PQ^(2)+QS^(2)}=13

Therefore, the answer is: The value of PS is 13.

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