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The principal would like to assemble a committee of 8 students from the 20-member student council. How many different committees can be chosen?

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Final answer:

The problem is a combinatorics question where the principal can choose 125,970 different committees of 8 students from a 20-member student council using the combination formula.

Step-by-step explanation:

This question is a classic example of a combination problem in mathematics, specifically combinatorics. To determine how many different committees can be chosen, we use the combination formula:

C(n, k) = n! / (k!(n-k)!)

where n is the total number of items to choose from, k is the number of items to choose, and ! denotes factorial.

In this case, there are 20 members in the student council and the principal wants to choose 8, so we plug those numbers into the formula:

C(20, 8) = 20! / (8!(20-8)!) = 20! / (8!12!) = 125,970

Therefore, there are 125,970 different ways the committee of 8 students can be chosen from the 20-member student council.

User Rama Vadakattu
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