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What is the solution of (4x+3)^2=18
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What is the solution of (4x+3)^2=18

User Stargateur
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(4x+3)^2=18\iff4x+3=\pm√(18)\\\\4x+3=-√(9\cdot2)\ \vee\ 4x+3=√(9\cdot2)\\\\4x+3=-\sqrt9\cdot\sqrt2\ \vee\ 4x+3=\sqrt9\cdot\sqrt2\\\\4x+3=-3\sqrt2\ \vee\ 4x+3=3\sqrt2\ \ \ \ \ \ \ \ |-3\\\\4x=-3-3\sqrt2\ \vee\ 4x=-3+3\sqrt2\ \ \ \ \ \ \ |:4\\\\\boxed{x=(-3-3\sqrt2)/(4)\ \vee\ x=(-3+3\sqrt2)/(4)}

User Slothrop
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