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The coordinates of the vertices of​ quadrilateral ABCD ​ are A(−4, −1) , B(−1, 2) , C(5, 1) , and D(1, −3) .

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The coordinates of the vertices of​ quadrilateral ABCD ​ are A(−4, −1) , B(−1, 2) , C-example-1
User Soffy
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1 Answer

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Hi there, KawallPotato! :)

Finding the slope of a line is finding the rise over run, or the change in y over the change in x. Let me show you what I mean.

Slope = change in y / change in x

Or in other words,
(y2 - y1)/(x2 - x1)

Let's try it with AB. The first thing to consider is the placement of the letters. The blank space is asking for the slope of point A to point B, which means that the coordinates of A are your y₁ and x₁ values and the coordinates of B are your y₂ and x₂ values.

Put them in the equation like this:


(2 - (-1))/(-1 - (-4))

2 - (-1) is a double negative, so it becomes 2 + 1, which is 3.

-1 - (-4) turns into -1 + 4 for the same reason. The change in x is also 3.


(3)/(3) = 1, so the slope of line AB is 1.


Using the same method, we can solve the next three problems.

Coordinates of B: (-1, 2)

Coordinates of C: (5, 1)

Slope:
(1 - 2)/(5 - (-1)) = (-1)/(5+1) = -(1)/(6)

The slope of BC is -1/6.


Coordinates of C: (5, 1)

Coordinates of D: (1, -3)

Slope:
(1 - (-3))/(5 - 1) = (1 + 3)/(5 -1) = (4)/(4), so the slope is 1.


Coordinates of A: (-4, -1)

Coordinates of D: (1, -3)

Slope:
(-1 - (-3))/(1 - (-4)) =  -(2)/(5)

The slope is
-(2)/(5).


Quadrilateral
ABCD is not a parallelogram because it has only one pair of parallel opposite sides.

I hope this was helpful. Have a great day. :D

User Davir
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